Question

✓3-1/✓3+1 rationalise the denominator​

Answer 1

ANSWER :

Rationalizing the denominator :

$\frac{ \sqrt{3 + 1} }{ \sqrt{3 - 1} } = \frac{ \sqrt{3 + 1} }{ \sqrt{3 - 1} } \times \frac{ \sqrt{3 + 1} }{ \sqrt{3 + 1} }$

$= > \frac{( \sqrt{3 + 1})( \sqrt{3 + 1}) }{ \sqrt{3 - 1} \times \sqrt{3 + 1} }$

$= > \frac{ { (\sqrt{3 + 1}) }^{2} }{ ({ \sqrt{3}) }^{2} - {1}^{2} } = \frac{3 + 1 + 2 \sqrt{3} }{3 - 1}$

$= > \frac{4 + 2 \sqrt{3} }{2} = 2 + \sqrt{3}$

Therefore, 2+√3 is the answer

Hope this helps you☺☺

Answer 2

Answer:

Step-by-step explanation:

We need to rationalize the givenequation

To rationalize we will multiply and divide the denominator by √3+1

(√3+1)√3+1)/(√3-1)(√3+1)

Denominator can be simplified using the identity (a2-b2)=(a-b)(a+b)

And the equation becomes

=(√3+1)2/(√3)2-(1)2

=(4+2√3)/2

=2+√3