3(1/3)^3 - 10(1/3)^2 - 27(1/3) +10. Please solve this with proper explanation i will give thanks and the answer should be 0.
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Step-by-step explanation:
hlo mate here's your answer
Consider the triangles △ABC and △PQR
ADandPMbeing the mediums from vertex AandPrespectively.
Given : △ABC∼ △PQR
To prove :
P Q
A B
=
PM
AD
It is given that △ABC∼ △PQR
⇒
P Q
A B
=
Q R
B C
=
P R
A C
[ from the side-ratio property of similar △ s]
⇒ ∠A= ∠P,∠B= ∠Q,∠C= ∠R
BC= 2BD;QR= 2 QM
[P,M being the mid points of BC q QR respectively]
⇒
P Q
A B
=
2 Q M
2 B D
=
P R
A C
⇒
P Q
A B
=
Q M
B D
=
P R
A C
Now in △ABDq△PQM
P Q
A B
=
Q M
B P..[ from (1)]
∠B= ..[ from (A)]
⇒ △ABD∼ △PQM
SAS
property of similar △s] from the side property of similar△s Hence proved
P Q
A B
=
PM
AD
i hope its help you mark as brainlist
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Answer:
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