Question

3-1/3[3x-3-1/4{7x+7-(5x-5)}]=10-2x​

Answer 1

$3-\frac{1}{3}[3x-3-\frac{1}{4}(7x+7-(5x-5)) ] = 10-2x$

Step 1: Simplify both sides of the equation.

$3-\frac{1}{3}[3x-3-\frac{1}{4}(7x+7-(5x-5)) ] = 10-2x$

(Distribute)

$3+\frac{-5}{6}x+2=10+-2x$

(Combine Like Terms)

$(\frac{-5}{6}x)+(3+2)=-2x+10$

$\frac{-5}{6} x+5=-2x+10$

Step 2: Add 2x to both sides.

$\frac{-5}{6} x+5+2x=-2x+10+2x$

$\frac{7}{6} x+5=10$

Step 3: Subtract 5 from both sides.

$\frac{7}{6} x+5-5=10-5$

$\frac{7}{6} x=5$

Step 4: Multiply both sides by $\frac{6}{7}$.

$\frac{6}{7}* \frac{7}{6} x=\frac{6}{7}* 5$

$x=\frac{30}{7}$

∴ The value of x = $\frac{30}{7}$