Question

( 3)1+3+5+7+ ..... Sumo
first 16 odd positie integers​

Answer 1

Answer:

n = 16

a = 1

d = 3 - 1 = 2

$= \frac{n}{2} (2a + (n - 1)d) \\ \\ = \frac{16}{2} (2 \times 1 + (16 - 1)2) \\ \\ = 8(2 + 30) \\ \\ = 8(32) \\ \\ = 64$

sum of first 16 odd positive numbers is 64

mark as Brainliest ❤️

Answer 2

64 yes 64 is the correct answer