Question

(3-1÷4-1)2

Answer me​

Answer 1

Answer:

=1553

Step-by-step explanation:

Given : Expression \dfrac{3\frac{1}{4}}{\{1\frac{1}{4}-\frac{1}{2}(2\frac{1}{2}-\frac{1}{4}-\frac{1}{6})\}}{141−21(221−41−61)}341

To find : Simplify the expression ?

Solution :

\dfrac{3\frac{1}{4}}{\{1\frac{1}{4}-\frac{1}{2}(2\frac{1}{2}-\frac{1}{4}-\frac{1}{6})\}}{141−21(221−41−61)}341

Simplify step by step,

=\dfrac{\frac{13}{4}}{\{\frac{5}{4}-\frac{1}{2}(\frac{5}{2}-\frac{1}{4}-\frac{1}{6})\}}={45−21(25−41−61)}413

=\dfrac{\frac{13}{4}}{\{\frac{5}{4}-\frac{1}{2}(\frac{30-3-2}{12})\}}={45−21(1230−3−2)}413

=\dfrac{\frac{13}{4}}{\{\frac{5}{4}-\frac{1}{2}(\frac{25}{12})\}}={45−21(1225)}413

=\dfrac{\frac{13}{4}}{\{\frac{5}{4}-\frac{25}{24}\}}={45−2425}413

=\dfrac{\frac{13}{4}}{\{\frac{30-25}{24}\}}={2430−25}413

=\dfrac{\frac{13}{4}}{\frac{5}{24}}=245413

=\dfrac{13\times 24}{4\times 5}=4×513×24

=\dfrac{78}{5}=578

=15\dfrac{3}{5}=1553

Therefore, \dfrac{3\frac{1}{4}}{\{1\frac{1}{4}-\frac{1}{2}(2\frac{1}{2}-\frac{1}{4}-\frac{1}{6})\}}=15\dfrac{3}{5}{141−21(221−41−61)}341