Question

(3^-1+4^-1)^3×(-14÷24)^-1

Please solve it fast

Answer 1

$( {3}^{ - 1} + {4}^{ - 1} )^{3} \times ( - 14 \div 24)^{ - 1} \\ = ( \frac{1}{ 3} + \frac{1}{4} )^{3} \times ( \frac{ - 14}{24} )^{ - 1} \\ = ( \frac{7}{12} )^{3} \times ( \frac{ - 7}{12} )^{ - 1} \\ = { (\frac{7}{12} })^{3} \times \frac{12}{ - 7} \\ = - \frac{7 \times 7 \times 7 \times12}{12 \times 12 \times 12 \times 7} \\ =- \frac{7 \times 7}{12 \times 12} \\ = -\frac{49}{144}$