Question

(3^-1+4^-1)+(5^-1)^0​

Answer 1

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$\implies \: a {}^{ - x} = ( \frac{1}{a} ) {}^{x}$

$\implies \: a {}^{0} = 1$

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$\implies(3 {}^{ - 1} + 4 {}^{ - 1}) + (5 {}^{ - 1} ) {}^{0} \\ \\ = ( \frac{1}{3} + \frac{1}{4}) + ( \frac{1}{5}) {}^{0} \\ \\ = (\frac{4 + 3} {12}) + 1 \\ \\ = \frac{7}{12} + 1 \\ \\ = \frac{7 + 12}{12} \\ \\ = \frac{19}{12}$

☆ Therefore your answer is 19/12.