Math, asked by meghnamathew13, 5 hours ago

(3^-1 + 4^-1 + 5^-1)^-1

Answers

Answered by nyctophiledaksh
1

Step-by-step explanation:

(3^-1 + 4^-1 + 5^-1)^-1

= (1/3+1/4+1/5)^-1

= [(20+15+12)/60]^-1

=(47/60)^-1

=60/47

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