Question

(3^-1+4^-1+5^-1)^2 please answer​

Answer 1

Step-by-step explanation:

$(3^{-1}+4^{-1}+5^{-1})^{2}$

= $(\frac{1}{3}+\frac{1}{4}+\frac{1}{5})^{2}$

= $(\frac{20+15+12}{60})^{2}$

= $(\frac{47}{60})^{2}$

= $\frac{2209}{3600}$