(3^=-1-6^-1)+(2^-1-6^-1)
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What are the next three numbers in the sequence 1/6, 1/3, 1/2, 2/3?
This sequence can be solved in two ways.
I will let you know both the ways so that you get an idea of solving a sequence in different ways.
Method 1
1\6
1/3 = 1/3*2/2 = 2/6
1/2 = 1/2*3/3 = 3/6
2/3 = 2/3*2/2 = 4/6
5/6
6/6 = 1
7/6
Next 3 numbers in the sequence are - 5/6, 6/6, 7/6
Method -2
Solving the fractions
1/6 = 0.1667 = 1/6
1/3 = 0.333 = 2/6
1/2 = 0.5 = 3/6
2/3 = 0.666 = 4/6
Difference between all these decimal numbers is 0.167
So, for next 3 numbers add 0.167 to each arriving number.
0.666+0.167 = 0.833 = 5/6
0.833+ 0.167 = 1 = 6/6
1+0.167 = 1.167 = 7/6
Next 3 numbers in the sequence are 5/6, 6/6, 7/6
I know that Method 2 is bit tough but you can also think like this for any question.
hope it will help you
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