Question

3. (1) 6 pipes are required to fill a tank in Ihr 20 minutes. How long will it take if only 5
pipes of the same type are used?
using the formula of direct and Inverse proportion​

Answer 1

Answer:

according to question :-

6:80: :5:x

so 6*x = 80*5

x = 80*5/6 = 40*5/3 = 200/3 = 66.66 minutes

66.66 min = 66.66/60 = 6666/6000 = 1.11 hrs

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Answer 2

Answer:

1 hour 36 minutes

Step-by-step explanation:

as you can imagine that: when the number of pipes increases the tank can be filled early that is the time taken to fill the thank reduces

hence it is problem of inverse proportion

which means that the no. of pipes and time taken to fill are inversely proportional

let X be the no. of pipes

let Y be the time taken by pipes

hence ,by indirect proportion we write

X Is inversely proportional to Y

that is XY = k

where k is the constant value

when X= 6 pipes, Y= 80 minutes

XY=k=6*80=480

similarly, when X=5, Y=?

we already know k value that is 480

X?=k

5*?=480

?=96

answer is 96 minutes that is 1 hour 36 minutes

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