3 1-COS X 1+ cos x х 1) tan 2. 2) tan 2 X 3) cot 2 4) cot 2
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Answer:
i am not sure
Explanation:
y=cot
−1
(
cos
x)−tan
−1
(
cos
x).
takingsinbothside
siny=sin[cot
−1
(
cos
x)−tan
−1
(
cos
x)]
sin[tan
−1
(
cos
x
1
)−tan
−1
(
cos
x)]
sin
⎣
⎢
⎢
⎢
⎡
tan
−1
1+
cos
x
1
×
cos
x
(
cos
x
1
−
cos
x)
⎦
⎥
⎥
⎥
⎤
sin[tan
−1
2
cos
x
(1−cosx)
]
sin[sin
−1
(
1+cosx
1−cosx
)]
=
1+cosx
1−cosx
=
2cos
2
2
x
2sin
2
2
x
siny=tan
2
2
x
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