Question

(-3,1) lies on a graph of the equation kx-3y+7=0, find k?​

Answer 1

Answer:

k = 4/3

Step-by-step explanation:

See..

as (-3,1) lies on the graph of equation kx-3y+7 = 0

so..

x should be taken as -3 in the equation and y should be taken as 1

Substituting the values of x and y in the equation we get...

k(-3) - 3(1) + 7 = 0

-3k -3 + 7 = 0

-3k + 4 = 0

so -3k = -4

3k = 4

so

k = 4/3

Answer 2

Step-by-step explanation:

k(-3)-3(1)+7=0

k(-3)-3+7=0

k(-3)+4=0

k(-3)=-4

k=-4/-3

k=4/3