Question

3+1/root3+1/3+root3+1/root3-3=

Answer 1

Answer:

answer is √4 is right answer

Answer 2

Answer:

3+1/root3+1/3+root3+1/root3-3

$3 + 1 \div \sqrt{3} + 1 \div 3 + \sqrt{3} + 1 \div \sqrt{3} - 3 =$

=>3+1/3-3+1/root3+1/root3+root3

=>1/3+2/root3+root3

=>1/3+2+(root3)^2/root3

=>1/3+2+3/root3

=>1/3+5/root3

=>root3+15/3root3

$= > \sqrt{3} + 15 \div 3 \sqrt{3}$

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