Question

-3
1. The air-pressure is equal to 75 cm column of mercury.
Express it in N m 2. Given g = 10 m s?, density of
mercury = 13.6 x 103 kg m
Ans. 1.02 x 105 N m 2
2. Calculate the pressure of sea-water at a depth of
200 m, when the average density of sea water is
1.032 × 103 kg m-3. (g = 9.8 ms 2
Ans. 2.023 x 10N m-2
3. The density of the atmosphere at sea level is
1.29 kg/mº. Assume that it does not change with
altitude, then how high would the atmosphere extend?
Ans. 7989 m.
2.
8 = 9.8 m/s2​

Answer 1

Answer:

1 \

Density of mercury is = 1.36 X104 kg/m3. h = height of mercury column which is given = 75 cm = 0.75 m. So pressure = 0.75 X 1.36 X104X9. 8 = 9.996X104Nm-2

Explanation: