Question

✔3 -1 upon ✔3+1 .....rationalize the denominator ​

Answer 1

Answer:

root3-1

root3+1

3+1-2root3 upon 2

4-2root3 upon 2

2-root3 is ur answer

Step-by-step explanation:

hope it helpfull to u

Answer 2

$= > \: \: \frac{ \sqrt{3} - 1}{ \sqrt{3} + 1 } \\ \\ = > \: \: \frac{ \sqrt{3} - 1}{ \sqrt{3} + 1} \times \frac{ \sqrt{3} - 1 }{ \sqrt{3} - 1 } \\ \\ = > \: \: \frac{ {( \sqrt{3} - 1 })^{2} }{( \sqrt{3} + 1)( \sqrt{3} - 1) } \\ \\ = > \: \: \frac{ {( \sqrt{3} })^{2} + {(1)^{2} } - 2 \sqrt{3} }{ {( \sqrt{3} })^{2} - {(1})^{2} } \\ \\ = > \: \: \frac{3 + 1 - 2 \sqrt{3} }{2} \\ \\ = > \: \: \frac{4 - 2 \sqrt{3} }{2} \\ \\ = > \: \: \frac{\cancel{2}(2 - \sqrt{3} )}{\cancel{2}} \\ \\ = > \: \: 2 - \sqrt{3}$