Question

Х
3
1 X 4
4
1 X 5
5
(a)
II
=
II
II
3
3x 2
6 3x3
9 3x4
123 x 5
15
t
1
2
3
4
5
Thus,
=
II
3 6 9
12
15
(f)
3
2.
5
4.
7
(b)
(c)
(d)
(e)
5
7
6
11
10
4. Circle the fraction which is not equivalent to the others:
21 9 3 12
15 5 45 10
(a)
(b)
49' 21' 7' 21
27' 9' 72' 18
18 3 9
9 15
(c)
14 1 6 3
(d)
20' 4' 12' 20
70 5 15 15
3
5. Find an equivalent fraction of with : (The first one has been
7
(a)
numerator = 15
denominator
3 3 x 5
3x5 15
7 7x 5
=
H
(b)​

Answer 1

Answer:

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