Question

3*10^11 electrons are flowing through the filament of bulb for two minutes . Find the current flowing through the circuit . Charge on one electron = 1.6*10^-10 C

Answer 1

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Answer 2

Answer:

3*10^11 electrons are flowing through the filament of the bulb for two minutes, the current flowing through the circuit will be $0.4A$

Explanation:

• Let I be the current flowing through an electrical circuit t be the time of flow and Q be the total charge.  

        We have the expression for the total charge as,

        $Q = It$    

        That is,

        $I = \frac{Q}{t}$       ...(1)

        Then we have another expression for Q as,

         $Q = ne$     ...(2)

        Where n is the number of electrons and e is the charge of one electron.

        We can use these equations for solving the given question.

• From the question,

       Number of electrons $n =3\times 10^{11}$

       Time, $t = 2min = 2\times 60 = 120s$

       Charge on an electron, $e = 1.6\times 10^{-10} C$

        Then,

        Substituting the given values into equation (2)

        $Q = 3\times 10^{11} \times 1.6\times10 ^{-10}=48C$

        Now, Using equation(1),

        $I = \frac{48}{120} = 0.4 A$