Question

3*10^11 electrons are flowing through the filament of bulb for two minutes . Find the current flowing through the circuit . Charge on one electron = 1.6*10^-10 C

Answer 1

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Number of electrons (n) = 3×10^11
Charge on each electron (e) = -1.6×10^-10 C
Time = 2 minutes = 120 seconds

Conventional Current (I) = q/t = ne/t =(3×10^11×1.6×10^-10)÷(120)
= (1.6×10)÷(40)
= 16/40 = 0.25 A

The current flowing through the filament will be 0.25 A

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Answer 2

Answer:

see answer from the photo