Question

3-(10(6+7÷(16-22))+2)​

Answer 1

Answer:

3-(10(6+7÷(16-22))+2)

Answer 2

Answer:

The solution of the given expression will be$\frac{-142}{3}$.

Step-by-step explanation:

Given: $3-(10(6+7\div(16-22))+2)$

We have to solve the above expression.

• By using the Bodmas rule, we are solving the above expression.
• As we know that the Bodmas rule is used to remember the order of operations to be followed while solving expressions in mathematics.

Where,

$\begin{array}{l}\mathrm{B}=\text{brackets}\\\mathrm{O}=\text { order of powers or rules } \\\mathrm{D}=\text { division } \\\mathrm{M}=\text { multiplication } \\\mathrm{A}=\text { addition } \\\mathrm{S}=\text { subtraction }\end{array}$

We are solving in the following way:

We have,

$3-(10(6+7\div(16-22))+2)$

Solving the above expression further we get,

$=>3-(10(6+7\div(-6))+2)\\\\=>3-(10(6+\frac{7}{-6} )+2)\\\\=>3-(10(\frac{6\times -6+7}{-6} ))+2)\\\\=>3-(10(\frac{-36+7}{-6} ))+2)\\\\=>3-(10(\frac{29}{6} )+2)\\\\=>3-(\frac{290}{6} +2)\\\\=>3-(\frac{145}{3} +2)\\\\=>3-(\frac{145+2\times3)}{3} )\\\\=>3-\frac{151}{3} \\\\=>\frac{3\times3-151}{3} \\\\=>\frac{9-151}{3} \\\\=>\frac{-142}{3}$

NOTE:

Q. Solve: 3-(10(6+7÷(16-22))+2)​