3 মাস অন্তর দেয় বার্ষিক 10% চক্রবৃদ্ধি হার সুদে 6250 টাকার 9 মাসের চক্রবৃদ্ধি সুদ হিসাব অরে লিখি।
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Step-by-step explanation:
Given 3 months interval Annual at the rate of 10% compound interest on Rs. 6,250 for 9 months compounded
- So p = 6250
- r = 10
- t = 9/12 = ¾ years
- n = 12/3
- n = 4
- So we have
- Compound Interest = P (1 + r / n x 100)^nt – p
- = 6250 (1 + 10 / 4 x 100)^4 x ¾ - 6250
- = 6250 (41 / 40)^3 – 6250
- = 6250 [ (41 / 40)^3 – 1]
- = 6250 (1.076890625 – 1)
- = 6250 x 0.076890625
- = Rs 480.56
Reference link will be
https://brainly.in/question/5450119
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