Question

3. 10. A force of 15 N acts for 5s on a body of mass 5Kg which is initially at rest. Calculate. a) final velocity of the body b) the displacement of the body

Answer 1

first acceleration => force /mass = 15/5 = 3m/s2
a)final velocity (v) = v=u+at
=>v=0+3*5=> 15m/s
b)displacement (s)= v^2=u^2+2as
=> 15^2= 0+2*3*s
=>225= 15s
therefore s= 225/15= 15metre
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