Question

3. 10 g of a sample of conc. hydrochloric acid (HCI) solution diluted with water, was added to a piece of marble (CaCO3) weighing 7.0 g. After completion of the reaction, 2.8 g of marble remained unreacted. What was the percentage strength of the conc. acid ? (H = 1; Cl = 35.5; Ca = 40; C = 12; 0 = 16]​

Answer 1

Explanation:

Solution :-

\begin{gathered}Step 1 : - \: \: x = > \frac{ - 1}{3} \\ \\Step 2 : - \: 3( \frac{ - 1}{3}) + 1 \\ \\Step 3 : - \: \cancel {3} (\frac{ - 1}{\cancel {3}} ) + 1 \\ \\Step 4 : - \: - 1 + 1 = > 0 \\ \\ = > 0\end{gathered}Step1:−x=>3−1Step2:−3(3−1)+1Step3:−3(3−1)+1Step4:−−1+1=>0=>0

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