Math, asked by mayankray503, 9 months ago

3/10 of a wall was completed on 1 day, 4/14 was completed on day 2 and 3/15 of the wall on day 3. if the total length of the wall is 513 1/3m,find 1)what part of the wall constructed on day 4 2) how many metres was constructed on day 4

Answers

Answered by Anonymous
15

Answer:

day 1 = 3/10 × 1540/3 = 4620/30 = 154 m

day 2 = 4/14 × 1540/3 = 6160/42 = 146.66 m

day 3 = 3/15 × 1540/3 = 4620/45 = 102.66 m

now , day 4 = 154+146.66+102.66 = 403.22 m

and , total wall = 513.33m

so , day 4 = 513.33-403.22 = 110.11 m

and in division form = 513.33/110.11

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