(3^100+3^101+3^102)/(3^99+3^98-3^97)=351/11
Prove this statement bye proper method please. For better understanding of question here's a image:-
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Answer:
351/11
Step-by-step explanation:
[3^100(1+3+3^2)]/ 3^97(3^2 + 3 -1)
3^3(13)/11
27(13)/11 = 351/11
manjunpai2000:
in the numerator
take 3^100 common
and from denominator take 3^97 common
100-97 =3
ie. 3^100-97 =3^3
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