Math, asked by kavyamaheshwari38, 1 year ago

(3^100+3^101+3^102)/(3^99+3^98-3^97)=351/11
Prove this statement bye proper method please. For better understanding of question here's a image:-

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Answers

Answered by manjunpai2000

Answer:

351/11

Step-by-step explanation:

[3^100(1+3+3^2)]/ 3^97(3^2 + 3 -1)

3^3(13)/11

27(13)/11 = 351/11

manjunpai2000: in the numerator

manjunpai2000: take 3^100 common

manjunpai2000: and from denominator take 3^97 common

manjunpai2000: 100-97 =3

manjunpai2000: ie. 3^100-97 =3^3

kavyamaheshwari38: Thanks a lot

manjunpai2000: welcome

kavyamaheshwari38: You do my so much help as I can't thanks you

kavyamaheshwari38: You are great

manjunpai2000: it's my pleasure

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