Math, asked by mahatvisaini007, 10 months ago

3√-108a^4 b^3 can any one
class 9​

Answers

Answered by Anonymous
1

Answer:

a to the power 4 b cube

To find:

Simplify cube root -108 a to the power 4 b cube in the simplest form

Solution:

From given, we have an equation,

cube root -108 a to the power 4 b cube

cube root of a negative number is a negative number.

∴ cube root -108 a to the power 4 b cube =

- cube root 108 a to the power 4 b cube

cube root of (b cube) = b

cube root of (a to the power 4) = \sqrt[3]{a^4}= \sqrt[3]{a^3 \times a}= a\sqrt[3]{a}

3

a

4

=

3

a

3

×a

=a

3

a

cube root of 108 = \sqrt[3]{108} = 3\sqrt[3]{4}

3

108

=3

3

4

∴ cube root -108 a to the power 4 b cube = -3∛4a∛ab

In equation form:

\sqrt[3]{-108a^4b^3} = -\sqrt[3]{108a^4b^3}=-3\sqrt[3]{4}\sqrt[3]{a^4}\sqrt[3]{b^3}=-3\sqrt[3]{4}a\sqrt[3]{a}b

3

−108a

4

b

3

=−

3

108a

4

b

3

=−3

3

4

3

a

4

3

b

Step-by-step explanation:

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