Math, asked by rajendranharini2594, 3 months ago

[{(3/11)^-3}]^-6 ii)[(2/3)^-1 + (2/5)^-1] ÷ (3/4)^-2​

Answers

Answered by akritigupta2004
0

Answer:

Step-by-step explanation:

[{(3/11)^-3}]^-6

= 3/11 ^-18

= 11/3^18

2) [(2/3)^-1 + (2/5)^-1] ÷ (3/4)^-2​

=3/2 ^1+ 5/2^1 ÷ 4/3 ^2

= 8/2÷16/9

=8/2× 9/16

=4× 3/4 =3

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