3 14 15
In the given circuit current through 90 Q resistor is
8 19 20
w
30
30 n
30 Ω
3 24 25
w
90
8 29 30
45 Ω
10 22
3 34 35
100 2
8 39 40
V= 50 V
44 45
19
1
Answers
Answer:
Correct option is C)
Explanation:
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Class 12
>>Physics
>>Current Electricity
>>Combinations of Cells and Problems on It
>>In the circuit shown, the current in the
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In the circuit shown, the current in the 1Ω resistor is :
299455
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Medium
JEE Mains
Updated on : 2022-09-05
Solution
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Correct option is C)
Step 1 : Applying KVL in loop 1
9−2i−1(i−i
1
)−3i=0
⇒6i−i
1
=9 ....(1)
Step 2 : Applying KVL in loop 2
6−3i
1
+1(i−i
1
)=0
⇒−i+4i
1
=6 ...(2)
Step 3 : Solving equations (1) and (2)
Eq (1)×4+ Eq(2)
⇒23i=42
⇒i=1.826A
Put the values of i in equation (1)
⇒6×1.826−i
1
=9
⇒i
1
=1.956A
Current through 1Ω resistor =i−i
1
=−0.13A
Therefore, current through 1Ω resistor is 0.13A from Q to P
Hence, Option (C) is correct.