Question

3/15
A metal pipe is 25 cm long. Inner diameter of cross section is 6 cm and thickness is 0.5 cm. Its outer curved surface area is​

Answer 1

Answer :-

• Outer CSA of Pipe = 550 cm²

Given :-

• Thickness of Pipe = 0.5 cm
• Inner Diameter of Pipe = 6 cm
• Length (Here Height) of Pipe = 25 cm

To Find :-

• CSA of Pipe = ?

Explanation :-

✦ In order to find the Outer CSA of the Pipe, First we need to find the Inner Radius of Pipe.

$\red { \boxed { \bf \bigstar \: Inner \: Radius = \dfrac{Diameter}{2} \: \bigstar }}$

$\rm \hookrightarrow Inner \: Radius = \dfrac{6}{2} \: cm = \bold{3 \: cm}$

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✦ Now we will find the Outer Radius of the Pipe.

$\green { \boxed { \bf \bigstar \: Outer \: Radius = Thickness + Inner \: Radius \: \bigstar }}$

$\rm \hookrightarrow Outer \: Radius = (0.5 + 3) \: cm = \bold{3.5 \: cm}$

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As we Know,

$\blue { \boxed { \bf \bigstar \: CSA \: of \: Cylinder = 2 \pi rh \: \bigstar }}$

$\rm \hookrightarrow \: 2 \pi rh = Outer \: CSA \: of \: Pipe$

$\rm \hookrightarrow \: 2 \times \dfrac{22}{7} \times 3.5 \times 25$

$\rm \hookrightarrow \: 2 \times 22 \times 0.5 \times 25$

$\rm \hookrightarrow \: 44 \times 12.5$

$\pink { \underline { \boxed { \bf \hookrightarrow \: 550 \: cm^2 }}}$

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Hence, the Outer CSA of the Cylindrical Pipe is 550 cm².