Question

3.15 g of oxalic acid in 4 litre of H2O find molarity​

Answer 1

mass of oxalic acid-3.15g

molar mass of oxalic acid-90g

moles ox=3.15/90=0.035

moles=Vox/22.4

Vox=0.035×22.4=0.784L

Vsoln=0.784+4=4.784L

Molarity= moles ox/Vol of soln

Molarity=0.035/4.784

Molarity=0.0073M

I hope this helps ( ╹▽╹ )