Question

3.16 g of impure sample of silver carbonate on being strongly heated yields silver weighing 1.68 g. the percentage purity of silver carbonate in the sample is ( atomic weight of Ag = 108) ​

Answer 1

Answer:

Ag

2

CO

3

(s)→2Ag(s)+CO

2

(g)+

2

1

O

2

(g)

Molecular Weight of Ag

2

CO

3

=276 g

And, molecular weight of Ag=2×108=216 g

276 g of Ag

2

CO

3

give 216 g Ag.

Therefore, 2.76 g of Ag

2

CO

3

on heating will give

276

216

×2.76 g=2.16 g Ag as residue.

Explanation:

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