Question

3 р
18. A drop of olive oil of
diameter 0.6x10^-3 m spreads
into a circular film of radius 12
cm. Estimate the molecular
size of olive oil.​

Answer 1

Explanation:

Given A drop of olive oil of  diameter 0.6 x 10^-3 m spreads  into a circular film of radius 12  cm. Estimate the molecular  size of olive oil.

• Given a drop of olive oil has a diameter 0.6 x 10^-3 m. We need to find the molecular size of olive oil.
• So diameter d = 0.6 x 10^-3 m
• So radius r = d/2 = 0.6 x 10^-3 / 2
•                              = 0.3 x 10^-3 m
• Now radius of circular film = 12 cm = 12 x 10^-2 m
• Now thickness of oil film = volume of oil drop / area of film.
•                                           = 4/3 π r^3 / π R^2
•                                          = 4/3 π (0.3 x 10^-3 )^3 / π x (12 x 10^-2)^2
•                                          = 4/3 x 0.027 x 10^- 9 / 144 x 10^-4
•                                          = 0.036 x 10^-9 / 144 x 10^-4
•                                         = 2.5 x 10^-9 m

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https://brainly.in/question/3137973