Question

3.18 g of copper on heating in air gave 3.98 g of black copper oxide. 1.06 g of copper oxide on reduction with hydrogen gave 0.847 g of copper. Show that these figures are in accordance with the law of definite proportions.

Answer 1

Answer:

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Answer 2

Answer:

2.42 gms of copper gives 3.025 gms of black oxide(CuO)

=> percentage of copper in cuo = 2.42/3.025  x 100 = 80%

=> percentage of oxygen in cuo = 100 - 80 = 20 %

Ratio of copper : oxygen = 80 : 20 = 4:1

Similarly ,

6.49 gms of black oxide gave 5.192 gm of copper

=> Percentage of copper in cuo = 5.192/6.49  x 100 = 80 %

percentage of oxygen in cuo = 100 - 80 = 20 %

Ratio of copper : oxygen = 80 : 20 = 4:1

Hence in both the reactions the ratio of copper : oxygen is same

Hence these figures are in accordance with law of constant proportion