Question

3. 18 years ago, the father was 9 times older
than his son. Now, the father is 3 times older
than his son. Find their present ages........
please help me......​

Answer 1

Answer:

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Step-by-step explanation:

Let the father's current age = x ( in yrs )

Let the son's current age = y ( in yrs )

x - 18 = 3( y - 18 )

3y - 54 = x - 18

3y = x + 36

y = x/ 3 + 12...(1)

x = 2y...(2)

sub (1) into (2)

x = 2 (x/3 + 12)

x = 2x/ 3 + 24

x/3 = 24

x=72

x=2y

y=x/2

y=72/2

y=36

the father's age is 72 years old on the son's age is 36 years old .

Therefore, sum of present ages of father and son = 36 + 72 = 108 yrs.