3+2√10 square root answer please.
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Step-by-step explanation:
I guess you are missing the iota.(i = root-1)
The correct question is:
3+2 root10i = (root5)² + (root2i)² + 2×root5×root2×i
=(root5 + root2i)²
Hence, Square root is root5 + root2i
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