Question

3.ײ- 16× + 64 = 0 solve this guys.​

Answer 1

Answer:

3x/\2 - 16x +64= 0

=>3x/\2 - 24 x + 8 x + 64 =0

=>3x (x - 8 )+ 8(x + 8)

=>(3x +8) ( x-8)

either , 3x +8=0. or x+8=0

=>x = -8/3. => x = -8

Answer 2

Answer:

$(x - 8) \: and \: (x - 8)$

Step-by-step explanation:

${x }^{2} - 16x + 64$

${x}^{2} - 8x - 8x + 64$

$x(x - 8) \: - 8(x - 8)$

$(x - 8) \: and \: (x - 8)$

$or \: (x - 8) ^{2}$