Question

3+2=165
2+1=123
4+2=286
5+3=2158
Then 6+1=?

Answer 1

Given:

3+2=165

2+1=123

4+2=286

5+3=2158

To find:

6 + 1 = ?

Solution:

Let us analyze the given terms one by one.

3+2=165

There are 3 parts the in the Right Hand Side:

First part is (First digit on LHS) - (Second digit on LHS) i.e. 3 - 2 = 1

Second part is (First digit on LHS) $\times$ (Second digit on LHS) i.e. 3 $\times$ 2 = 6

Third part is (First digit on LHS) + (Second digit on LHS) i.e. 3 + 2 = 5

2+1=123

There are 3 parts the in the Right Hand Side:

First part is (First digit on LHS) - (Second digit on LHS) i.e. 2 - 1 = 1

Second part is (First digit on LHS) $\times$ (Second digit on LHS) i.e. 2 $\times$ 1 = 2

Third part is (First digit on LHS) + (Second digit on LHS) i.e. 2 + 1 = 3

4+2=286

There are 3 parts the in the Right Hand Side:

First part is (First digit on LHS) - (Second digit on LHS) i.e. 4 - 2 = 2

Second part is (First digit on LHS) $\times$ (Second digit on LHS) i.e. 4 $\times$ 2 = 8

Third part is (First digit on LHS) + (Second digit on LHS) i.e. 4 + 2 = 6

5+3=2158

There are 3 parts the in the Right Hand Side:

First part is (First digit on LHS) - (Second digit on LHS) i.e. 5 - 3 = 2

Second part is (First digit on LHS) $\times$ (Second digit on LHS) i.e. 5 $\times$ 3 = 15

Third part is (First digit on LHS) + (Second digit on LHS) i.e. 5 + 3 = 8

Now, let us solve the given question:

6+1=?

First part is (First digit on LHS) - (Second digit on LHS) i.e. 6 - 1 = 5

Second part is (First digit on LHS) $\times$ (Second digit on LHS) i.e. 6 $\times$ 1 = 6

Third part is (First digit on LHS) + (Second digit on LHS) i.e. 6 + 1 = 7

So, the answer is 567.

6 + 1 = 567

Answer 2

Answer:

3+2=165 2+1=123 4+2=286 5+3=2158 6+1=