Math, asked by vidushi761, 1 day ago

(3+2√2)^2 + 1/(3+2√2)^2​

Answers

Answered by Anonymous
11

I HOPE IT'S HELPFUL FOR YOU!!!

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Answered by jayaprakash05
3

let,

x=3+2√2

1/(3+2√2)=x.

Rationalising the denominator..

1/x=1*(3-2√2)/(3+2√2)*(3-2√2).

=3-2√2 / 3(3-2√2)+2√2(3-2√2)

=3-2√2/ 9-6√2+6√2-4√4

=3-2√2/9-8

1/x =3-2√2 / 1

putting the values..

x+1/x = (3+2√2)+(3-2√2)

= 3+2√2+3-2√2

= 6.

squaring both the sides

(x+1/x)^2 = (x)^2+2*x*1/x+(1/x)^2

= x^2+2+1/x^2=6^2=36

= x^2+1/x^2=36-2=2.

Hope it helps..

PLZ mark me the brainliest..

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