(3+2√2)^2 + 1/(3+2√2)^2
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let,
x=3+2√2
1/(3+2√2)=x.
Rationalising the denominator..
1/x=1*(3-2√2)/(3+2√2)*(3-2√2).
=3-2√2 / 3(3-2√2)+2√2(3-2√2)
=3-2√2/ 9-6√2+6√2-4√4
=3-2√2/9-8
1/x =3-2√2 / 1
putting the values..
x+1/x = (3+2√2)+(3-2√2)
= 3+2√2+3-2√2
= 6.
squaring both the sides
(x+1/x)^2 = (x)^2+2*x*1/x+(1/x)^2
= x^2+2+1/x^2=6^2=36
= x^2+1/x^2=36-2=2.
Hope it helps..
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