Question

3^2-2^2)*(2/3)^-3
in fraction form

Answer 1

Heya !

Here's your answer !!


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$( \: {3}^{2} \: - \: {2}^{2} \: ) \: \times \: ( \: \frac{2}{3} \: )^{ - 3} \\ \\ = > ( \: 9 \: - \: 4 \: ) \: \times \: ( \: \frac{3}{2} \: )^{3} \\ \\ = > 3 \: \times \: \frac{3 \times 3 \times 3}{2 \times 2 \times 2 } \\ \\ = > \: 3 \: \times \: \frac{27}{8} \\ \\ = > \: \frac{81}{8} \: \: \: \: \: \: \: \: \: \: \: \: ans$


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Thanks!!

Answer 2

$hey \: mate \: here \: is \: your \: answer \\ \\ ( {3}^{2} - {2}^{2} ) \times ( {2 \div 3})^{ - 3} \\ \\ by \: using \: identity \: ( {a}^{2} - {b}^{2} ) = (a + b)(a - b) \\ \\ (3 + 2)(3 - 2) \times {(1 \div (2 \div 3))}^{3} \\ \\ 5 \times 1 \times{( 3 \div 2)}^{3} \\ \\ 5×27\div 8 \\ \\135\div8\\ \\ 16.875 \\ \\ hope \: \: it \: will \: help \: you \: mark \: me \: brainliest$
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