Question

3+2√2/3-2√2=a-b√2 find the value of a and b ​

Answer 1

(3+2)(3+2)/(3+2)(3-2)

9+62+2/9-2

11+6 2/7

a=11/7

b=6/7

Answer 2

$\huge\bold{ANSWER~:}$

$\frac{3 + 2 \sqrt{2} }{3 - 2 \sqrt{2} } = a - b \sqrt{2} \\ \\ \frac{3 + 2 \sqrt{2} }{3 - 2 \sqrt{2} } \times \frac{3 + 2 \sqrt{2} }{3 + 2 \sqrt{2} } = a - b \sqrt{2} \\ \\ \frac{ {(3 + 2 \sqrt{2)} }^{2} }{9 - 8} = a - b \sqrt{2} \\ \\ \frac{9 + 12 \sqrt{2} + 8 }{1}= a + b \sqrt{2}$

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