Question

3-2√2/3+2√2 rationalise the denominator​

Answer 1

Answer:

17-12√2

Step-by-step explanation:

3-2√2/3+2√2

⇒3-2√2/3+2√2x 3-2√2/3-2√2

⇒(3-2√2)²/9-8

⇒9+8-12√2

⇒17-12√2

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Answer 2

$\huge{\boxed{\bold{ANSWER~:}}}$

$= \frac{3 - 2 \sqrt{2} }{3 + 2 \sqrt{2} } \\ \\ = \frac{3 - 2 \sqrt{2} }{3 + 2 \sqrt{2} } \times \frac{3 - 2 \sqrt{2} }{3 - 2 \sqrt{2} } \\ \\ = \frac{ {(3 - 2 \sqrt{2} )}^{2} }{9 - 8} \\ \\ = \frac{9 - 12 \sqrt{2} + 8 }{1} \\ \\ = 17 - 12 \sqrt{2}$

${\large\color{Red}{Answer~is~17-12\sqrt{2} }}$