Question

(3√2-2√3)²
(3√2)²-(2√3)²

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Answer 1

$(3 \sqrt{2 } - 2 \sqrt{3} ) {}^{2} =( 3 \sqrt{2} ) { }^{2} - (2 \sqrt{3)} {}^{2} + 2 \times 3 \sqrt{2} \times 2 \sqrt{3}$

$(3 \sqrt{2} ) { }^{2} - (2 \sqrt{3} ) { }^{2} =( 3 \sqrt{2} + 2 \sqrt{3} ) \: \: (3 \sqrt{2} - 2 \sqrt{3} )$

it may help you

Answer 2

square(3√2)+square(2√3)-2*3√2*2√3

=18+12-12√6

=30-29.39

=0.61

square (3√2)-square(2√3)

=18-12

6