Math, asked by Yashoram, 9 months ago

3√2-2√3/3√2+2√3 rationalising the denominator​

Answers

Answered by sweta7399
1

Answer:

3√2-2√3/3√2+2√3. 3√2-2√3/3√2-2√3

(3√2-2√3)^2/(3√2)^2-(2√3)^2

applying the algebraic identities..

18+12-12√6/18-12

30-12√6/6

5-12√6

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