(3,-2),(-2,8)and (0,4) are colliner
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If the three points are collinear, the area of the triangle formed by the points is 0.
A = 1/2 [x1(y2- y3) + x2(y3- y1) + x3(y1- y2)]
x1=3 , y1=-2
x2=-2, y2=8
x3=0, y3=4
A= 1/2[3(8-4)+(-2)(4-(-2))+0(-2-8)]
A= 1/2[3×4+(-2)×6+0×-10]
A= 1/2[12+(-12)+0]
A=1/2[0]
A=0
so these two coordinates are collinear.
A = 1/2 [x1(y2- y3) + x2(y3- y1) + x3(y1- y2)]
x1=3 , y1=-2
x2=-2, y2=8
x3=0, y3=4
A= 1/2[3(8-4)+(-2)(4-(-2))+0(-2-8)]
A= 1/2[3×4+(-2)×6+0×-10]
A= 1/2[12+(-12)+0]
A=1/2[0]
A=0
so these two coordinates are collinear.
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