Question

(√3+√2)^2 expand this​

Answer 1

Answer:

Given

$( \sqrt{3} + \sqrt{2} ) {}^{2}$

We know

$x {}^{2} + y {}^{2} = x {}^{2} + 2xy + y {}^{2}$

Using here we get

x =

$\sqrt{3}$

and y =

$\sqrt{2}$

So,

$( \sqrt{3} + \sqrt{2} ) {}^{2} \\ = ( \sqrt{3} ) {}^{2} + 2 \times \sqrt{3} \times \sqrt{2} + ( \sqrt{2} ) {}^{2} \\ = 3 + 2 \times \sqrt{3 \times 2} + 2 \\ = 3 + 2 \sqrt{6} + 2 \\ = 3 + 2 + 2 \sqrt{6} \\ = 5 + 2 \sqrt{6}$

Answer 2

Answer:

3 + 2 + (2 × root3 ×root2)

5+2root6