Question

√3÷2√2 prove that it is irrational​

Answer 1

hey mate your answer here....

Step-by-step explanation:

Let us assume that n=√3÷2√2 is rational number.

therefore mx2√2 =√3 is also rational number.

but, √3 is an irrational number.

therefore our assumption is wrong .

√3÷2√2 is an irrational number.

hope it helps....

Answer 2

Step-by-step explanation:

let us assume that

$\sqrt{3} \div 2 \sqrt{2} \: is \: a \: rational \: number$

therefore,

$\sqrt{3} \div 2 \sqrt{2} can \: be \: expressed \: in \: form \: of \: p \div q \: where \: p \: and \: q \: are \: co \: primes \: and \: q \: is \: not \: equal \: to \: 0$

therefore,

$\sqrt{3} \div 2 \sqrt{2} = p \div q \: \\ 2 \sqrt{2} = p \div (q \times \sqrt{3} ) \\ \ \sqrt{2} = p \div (2q \sqrt{3} ) \\ since \: \sqrt{2} \: is \: an \: irrational \: number \: and \: beacause \: of \: sign \: of \: equality \\ \sqrt{3} \div 2 \sqrt{2} \: is \: an \: irrational \: number$