Question

√3-2√2 simplify ....

Answer 1

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Here is u r Ans ➡

$= \sqrt{3 - 2} \sqrt{2}$

$= \sqrt{(3 - 2)2}$

$= \sqrt{1 \times 2}$

$= \sqrt{2} \\ in \: decimal \: form \: > \: 1.41421$
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Answer 2

The answer is √2 + 1

Explanantion:

√3-2√2

= √((2+1) -2 √2)

= √{√(2)^2 + 1 ^ 2 - 2  √(2) (1)}

Since 2 can be written as √(2)^2 and 1 can be written as 1^2)

As (a+b)^2 = a^2 + b^2 + 2ab);

Now, it results as:

[√(2+1)]^2

= (√2+1)^1/2*2

=[√2+1]^2/2

=[√2+1]^1

=√2+1