Math, asked by nehal5055, 9 months ago

3-2 ✔2 upon 3+2✔2
rationalize the denominator ​

Answers

Answered by DrNykterstein
3

 =  >  \:  \:  \frac{3 - 2 \sqrt{2} }{3 + 2 \sqrt{2} }  \\  \\  =  >  \:  \:  \frac{3 - 2 \sqrt{2} }{3 + 2 \sqrt{2} }  \times  \frac{3 - 2 \sqrt{2} }{3  -  2 \sqrt{2} }  \\  \\  =  >  \:  \:  \frac{ {(3 - 2 \sqrt{2} })^{2} }{(3 +  2\sqrt{2})(3 - 2 \sqrt{2})  }  \\  \\  =  >  \:  \:  \frac{ {3}^{2} +  {(2 \sqrt{2}) }^{2}   - 12 \sqrt{2} }{ {(3)}^{2} -  {(2 \sqrt{2} })^{2}  }  \\  \\  =  >  \:  \:  \frac{9 + 8 - 12 \sqrt{2} }{9 - 8}  \\  \\  =  >  \:  \:  \frac{17 - 12 \sqrt{2} }{1}  \\  \\  =  >  \:  \: 17 - 12 \sqrt{2}

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