Question

3+√2,3-√2=0,,then find qudratic polynomial​ ​

Answer 1

Let @ and ß be the zeros of required polynomial.

=>@=3+√2 and. ß=3-√2

Now,

Sum of zeros:

@ + ß=(3+√2)+(3-√2)=3+3=6

Product of zeros:

@ß=(3+√2)(3-√2)=(3)^2-(√2)^2=9-2=7

Required polynomial:

x^2-(@+ß)x+@ß

=x^2-6x+7