(√3+√2)(√3-√2)=1 find value of
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Given:
(√3+√2)(√3-√2)=1
Solution:
Take L.H.S to simplify.
→(√3+√2)(√3-√2)
→(√3×√3)-(√3×√2)+(√2×√3)-(√2√2)
→(3)-(2)
→1
Hence L.H.S = R.H.S
✷Second method
we also know that (a-b)(a+b) = a²-b²
→√(√3+√2)(√3-√2)
→(√3)²-(√2²)
→3-2
→1
Hence proved!
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